Do you mean (3ax-15a)+(x-5)?
If so, then this is simply a matter of factoring by grouping, which you should have learned in pre-algebra.
You should show these steps in your work:
1. (3ax-15a)+(x-5)- beginning equation
2. 3a(x-5)+1(x-5)- factoring it out
3. (3a+1)(x-5)- rule of factoring by grouping
You should learn this method, because it is very simple and helps you a lot in factoring chapters.
False
3x
(x + 8)(x - 5)
x2 + 12x + 32 = (x + 8)(x + 4)
(5x - 1)(x + 6)
Factor the polynomial x2 - 10x + 25. Enter each factor as a polynomial in descending order.
(3x + 4)(3x + 4)
(x + 8)(x + 1)
(x+1)(x+9)
(x-2)(x-3)
(x-3)(x+8)
(x - 3)(x - 3)
(x + 8)(x + 1)
(x-4) (x+7)
2x+5x-24 7x2-24
The only factor is 2. 2*(t3 + 2t2 + 4x)
False