(x+8)(x-5)
(x + 8)(x - 5)
Start by looking for a common factor. Separate this factor, then factor the remaining polynomial.
It is x^2 -4 = (x-2)(x+2) when factored and it is the difference of two squares
That trinomial is unfactorable (the roots are not integers).
(x+8)(x-5)
(x + 8)(x - 5)
(x + 2)(x - 9)
(X+9)(x-2)
(x + 2)(x - 8)
(x + 2)(x - 7)
-70
(5x + 2)(x + 1)
-((x + 2)(x - 9))
(x - 3)(x + 6)
(x+6)(X+20)
(4x + 5)(x - 3)