I assume that you're talking about surface area. If so, imagine making a cylinder out of paper. You would have two circles, and between them a rectangle rolled up, right? So let's address the circles first. If the radius is 6 cm, then each circle's area (pi x radius squared) is: pi x (6 x 6) = 36pi = 113 sq cm Now we need to address the rectangle. Picture unrolling it. We would have a rectangle with a height of 5 cm and a length equal to the circumference of the base, right? So figure out the circumference. It (pi x D) is: pi x (2 x 6) = 12pi = 37.7 cm The area of the rectangle (base x height) is: 37.7 x 5 = 188.5 sq cm So, to get the total surface area, we add the rectangle (188.5 cm) and the TWO bases (113 sq cm x 2 = 226 sq cm), or 188.5 + 226 = 414.5 sq cm, rounded to the nearest, 415 sq cm
Area of whole circle = pi*r2 = 64*pi Area of Sector = Area of Whole Circle * Angle of Sector/Angle of Whole Circle = Area of Whole Circle * 120/360 = Area of Whole Circle / 3 = 64*pi/3 = 67.0 to the nearest tenth.
when rounding to the nearest whole number 0.49 ~ 0 as anything lower than .5 you round down to the nearest whole number anything that is .5 or over you round up. if you'd asked about 0.50, then the nearest whole number is 1
The area is 157 square meters rounded to the nearest whole number.
The answer is given below.
You're essentially trying to calculate the diameter of a cylinder with a hole in the middle. There are two formulas for volume which you need. Volume= Pi * r2 * h (where Pi=3.142, r = radius of the coil, h = width of the coil) Volume= Weight/Density Since both these formula equal Volume: Weight/Density= Pi * r2 * h Since the weight you have is for a cylinder with a hole in it, you need to calculate the volume of the whole cylinder (without the hole) and subtract the volume of the hole. So for a steel coil Weight/Density = (Pi * rc2 * h)-(Pi * rh2 * h) where rc= the radius of the coil and rh = the radius of the hole (Radius=diameter/2) you're trying to calculate the radius of the coil, so rearrange the formula to get: ((Weight/Density)/Pi*h) + rh2 = rc2 The diameter of the coil = 2 *rc NOTE:- It's important to keep your units of measure consistent throughout the calculation. Density is generally represented by kilograms per cubic metre (kg/m3) - for us metric users ;-) Therefore keep your coil weight in kgs and your radius / width measures in metres.
475 cubic feet
The volume of this cylinder is: 550 cubic units.
Surface area = 2 x Pai x radius x height = 2 x 3.14 x 11 x 11 = 759.88 = 760 SQ inch
527.52 but if you have to round it to a whole number the answer will then be 528
What is the volume of the cone to the nearest whole number.76cm,90cm?Improved Answer:-It will depend on the radius of the cone because its volume = 1/3*pi*radius2*height
Its radius is: 1298/2*pi = 207 meters to nearest whole number
113 (Nearest Whole Number)
Formula for calculating the volume of a cylinder = pi*radius2*length giving your answer in cubic units. Therefore: pi*42*9 = 452.3893421 cubic units. To the nearest whole number: 452 cubic units.
Volume = 1/3*pi*62*8 = 302 cubic inches to the nearest integer
Radius: 220/2pi = 35 cm
Radius of circle: 371/2*pi = 59 units to the nearest whole number
Imagine taking the ends off the cylinder, cutting the side down from end to end and unrolling the side; this creates a rectangle with the height of the cylinder along one edge and the circumference of the end along the other. Thus area of side = circumference × height. The ends of the cylinder are circles, thus: area = π × radius² → radius = √(area ÷ π) circumference = 2 × π × radius → circumference = 2 × π × √(area ÷ π) = 2 × √(area × π) → area side = 2 × √(area × π) × height → surface area of cylinder = 2 × area ends + area side → surface area = 2 × 11 units² + 2 × √(11 units² × π) × 11 units → surface area = 22 + 22 × √(11π) units² → surface area ≈ 22 + 129.33 units² ≈ 151 units²