The area is 157 square meters rounded to the nearest whole number.
An oval, or more technically an ellipse, has a long ( major) axis and short (minor axis). If major axis length is a and minor length is b, then area, A is A = pi*a*b /4 where and so the area of half an oval is pi*a*b/8
By taking a coordinate system with origin at the center of the ellipse, and x-axis along the major axis, and y-axis along the minor axis, then the ellipse intercepts the x-axis at -5 and 5, and the y-axis at -2 and 2. So that the equation of the ellipse x2/a2 + y2/b2 = 1 becomes x2/52 + y2/22 = 1 or x2/25 + y2/4 = 1.
first of all, learn how to spell. major* and secondly there isnt a difference. minor sounds like a major and a major sounds like a minor... and learn how to spell minor as well.
A simple question with a horrendously complicated answer. Short of carrying out elliptical integrals, the best I can suggest is the Ramanujan approximation according to which: Perimeter = pi*{3(a + b) - sqrt[10ab + 3(a2 + b2)]} where a and b are the semi-major and semi-minor axes. Substituting a = 15 mm and b = 6 mm gives Perimeter = 69.04 mm. A quick and easy, but roughly approximate method is as follows: The ellipse is between a circle of diameter 30 mm and one of 12 mm. Averaging these two gives a diameter of 21 mm. A circle with a 21 mm diameter has a circumference (perimeter) of 65.97 mm.
-0.999999 repeating Actually -0.999999 repeating is not the biggest number. How can anyone know that? Well, as every one knows the more further you go down the number line the more smaller the numbers get. So what you are looking for is the number most nearest to zero. However, we have a minor problem. Your number could range within: 0.01 to 0.00000000000000000000000000000000000000000001 I do not think that your school will let you put that many zeroes in front of the 1. But the more zeroes you put in front of the 1, the more the negative number gets bigger.
The area is 157 square meters.
The major axes of an ellipse is its longest diameter. The minor axes, on the other hand, is the shortest diameter.
2, major & minor. (Yes, really!)
The area of an ellipse with a major axis 20 m and a minor axis 10 m is: 157.1 m2
The major axis and the minor axis.
Moment of inertia about x-axis for an ellipse is = pi*b^3*a /4. Where b is the distance from the center of the ellipse to the outside tip of the minor axis. a is the distance from the ceneter of the ellipse to the outside tip of the major axis. Moment of inertia about x-axis for an ellipse is = pi*b^3*a /4. Where b is the distance from the center of the ellipse to the outside tip of the minor axis. a is the distance from the ceneter of the ellipse to the outside tip of the major axis.
pi x the minor radius x the major radius
Area = pi*a*b where a and b are the semi-major and semi-minor axes.
It is pi*a*b where a and b are the lengths of the semi-major and semi-minor axes.
Area = pi*a*b where a and b are the semi-major and semi-minor axes.
-- the eccentricity or -- the distance between the foci or -- the ratio of the major and minor axes
Circular segment