Yes. Every even number has a factor of 2.
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Numbers that have 2 as a factor are those that are divisible by 2 without leaving a remainder. This includes all even numbers such as 2, 4, 6, 8, 10, and so on. In other words, any number that can be expressed as 2 multiplied by another integer is a number that has 2 as a factor.
Can't quite tell what you mean by n3. 1) If that's n3, then: If n3 is even, it can be expressed as n * n * n = 2 * t (t is a natural number). You can see that two is a factor of n3, and so it has to be a factor of n, because there is no ther number that could contribute to it. So n is even too. 2) If you mean 3 * n, then: 3 * n = 2 * t, where t is a natural number. Again, the only number to contribute factor 2 for the right side of equation is n. So n has to be even too.
No. because odd numbers don't have 2 as a factor but even numbers do. So it won't be a whole number.
2 is an even number. I believe your confusion comes from the fact that 2 is a prime number, but it is still even. It is the only even number that is prime.
For a greatest common factor of 33, the number 66 (2 x 33) would be a smaller multiple than 99 (3 x 33).