Can't quite tell what you mean by n3. 1) If that's n3, then: If n3 is even, it can be expressed as n * n * n = 2 * t (t is a natural number). You can see that two is a factor of n3, and so it has to be a factor of n, because there is no ther number that could contribute to it. So n is even too. 2) If you mean 3 * n, then: 3 * n = 2 * t, where t is a natural number. Again, the only number to contribute factor 2 for the right side of equation is n. So n has to be even too.
No. because odd numbers don't have 2 as a factor but even numbers do. So it won't be a whole number.
2 is an even number. I believe your confusion comes from the fact that 2 is a prime number, but it is still even. It is the only even number that is prime.
For a greatest common factor of 33, the number 66 (2 x 33) would be a smaller multiple than 99 (3 x 33).
If m * n is even, it can be expressed as m * n = 2 * t, where t is natural number. Either m or n has to provide factor of 2 for the right side of equation, so it basically means at least one of them has to be even.
2 is a factor of every even number. Adding or subtracting one from an even number leaves an odd number. Since even and odd numbers alternate, 2 will be a factor of every other number.
That's the definition of an even number. If they didn't have 2 as a factor, they wouldn't be even.
because 70 is an even number, and every even number has 2 as a factor.
By definition, every even number has 2 as a factor. That means that every set of even numbers will have at least 2 as a common factor. The GCF might be higher, but if it has 2 as a factor, it's even.
Yes.
Every number to which 2 is a factor. Therefore, every multiple of two; hence, every even number.
Possiblilty is almost 1/2 cause every two numbers is a number with a factor of 2.From 2: 2,3,4,5,6,7,8,9,10...
It's easy to see whether 2 is a factor of a number because 2 is a factor of every even number and not a factor of any odd number.
Even numbers, by definition, are divisible by 2. That means that every even number has at least one 2 as a factor. If every even number has one, then any set of even numbers will have at least one 2 as a common factor. Since that number has two as a factor, it's even.
Think about it!
Any and every even number.
Can be divided by itself