NO!!!
Sine40 = Cosine50 = 0.64278...
Sin30 = Cos 60 = 0.5
Sin 0 = Cos 90 = 0
Sin 90 = Cos 0 = 1
From Latin the word 'Sine' means 'curve'. Cosine means 'Complimentary Sine' or Complimentary curve'.
The 'awkward' decimal numbers are based on a the radius of a circle, that radius being the hypotenuse of a right- triangle based at the circles origin/centre.
It is:- sin(40) = 0.6427876097
40
To determine which is greater between 50% of 40 and 40% of 50, we can calculate the actual values. 50% of 40 is 0.50 x 40 = 20. 40% of 50 is 0.40 x 50 = 20. Therefore, both values are equal at 20.
sin(40o) = 0.6428
135
Like normal expansion of brackets, along with: cos(A + B) = cos A cos B - sin A sin B sin(A + B) = sin A cos B + cos A sin B 5(cos 20 + i sin 20) × 8(cos 15 + i sin 15) = 5×8 × (cos 20 + i sin 20)(cos 15 + i sin 15) = 40(cos 20 cos 15 + i sin 15 cos 20 + i cos 15 sin 20 + i² sin 20 sin 15) = 40(cos 20 cos 15 - sin 20 cos 15 + i(sin 15 cos 20 + cos 15 sin 20)) = 40(cos(20 +15) + i sin(15 + 20)) = 40(cos 35 + i sin 35)
sine 40° = 0.642788
cos 71
Sadly, no. 20 does not equal 611, 40 does not equal 611, and just now, I can't think of any mathematical operation that could be applied to 20 and 40 with a result of 611.
20% of 40 is not greater than 40% of 20. The two are equal. 20% of 40 = 0.20 * 40 = 8 40% of 20 = 0.40 * 20 = 8
sin(angle) = opposite/hypotenuse → hypotenuse = opposite/sin(angle) opposite = rise → hypotenuse = 40ft / sin 16.5° ≈ 140.84 ft
20 and 20
62
20
No. All equilateral and equiangular triangles are acute. (All angles are equal to 60°, which is less than a right angle [90°]); however, the converse (which is what was asked) is not true.A triangle can have all three angles be less than 90°, but not be an equilateral triangle.An example is a triangle with angles of 80°, 60°, and 40°. It is scalene and acute.From the Law of Sines: a/sin(A) = b/sin(B) = c/sin(C), you can show that sin(80°) does not equal sin(60°) or sin(40°), so none of sides a, b, and c, are equal.You could have an acute isosceles triangle like: 80°, 80° and 20° angles, as another example. From the Law of Sines, you can show that two of the sides are equal, but the third side (opposite the 20° angle) is not equal to either of the other 2.
20 x 2 = 40
360