cos 71
The cofunction of the complement of cos 89° is sin 1°. This is because the complement of 89° is 1° (90° - 89° = 1°), and the cofunction identity states that (\cos(θ) = \sin(90° - θ)). Therefore, (\cos(89°) = \sin(1°)).
The cofunction identity for cosine states that the cosine of an angle is equal to the sine of its complement. Specifically, this can be expressed as (\cos(t) = \sin\left(\frac{\pi}{2} - t\right)) in radians or (\cos(t) = \sin(90^\circ - t)) in degrees. This relationship highlights the complementary nature of the sine and cosine functions.
Sin(19) = 0.3256 approx.
Sin theta of 30 degrees is1/2
My calculator tells me that sin 58 degrees = 0.84805
The cofunction of cosine is sine. Therefore, the cofunction of (\cos 70^\circ) is (\sin(90^\circ - 70^\circ)), which simplifies to (\sin 20^\circ). Thus, (\cos 70^\circ = \sin 20^\circ).
The cofunction of the complement of cos 89° is sin 1°. This is because the complement of 89° is 1° (90° - 89° = 1°), and the cofunction identity states that (\cos(θ) = \sin(90° - θ)). Therefore, (\cos(89°) = \sin(1°)).
cos 60
The cofunction identity for cosine states that the cosine of an angle is equal to the sine of its complement. Specifically, this can be expressed as (\cos(t) = \sin\left(\frac{\pi}{2} - t\right)) in radians or (\cos(t) = \sin(90^\circ - t)) in degrees. This relationship highlights the complementary nature of the sine and cosine functions.
Sin(19) = 0.3256 approx.
sine 10. Use the cofunction with the complementary angle.
sec x - cos x = (sin x)(tan x) 1/cos x - cos x = Cofunction Identity, sec x = 1/cos x. (1-cos^2 x)/cos x = Subtract the fractions. (sin^2 x)/cos x = Pythagorean Identity, 1-cos^2 x = sin^2 x. sin x (sin x)/(cos x) = Factor out sin x. (sin x)(tan x) = (sin x)(tan x) Cofunction Identity, (sin x)/(cos x) = tan x.
sin 57 degrees
all sin is sin97 degrees Fahrenheit = 36.1 degrees Celsius
Sin(X) = 0.9 X = Sin^(-1) 0.9 X = 64.158... degrees.
cos(α) = sin(90° - α) → cos(16° + θ) = sin(90° - (16° + θ)) = sin(74° - θ) → sin(36° + θ) = cos(16° + θ) → sin((36° + θ) = sin(74° - θ) → 36° + θ = 74° - θ → 2θ = 38° → θ = 19° → θ = 19 °+ 180°n for n= 0, 1, 2, ...
Sin theta of 30 degrees is1/2