Each 0 or 1 is a bit (bit being short for "binary digit")
a byte is 8 of these (byte being short for "binary eight")
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To take the 2's complement:Invert 1's and 0's (change each 1 to a 0, and each 0 to a 1).Add 1 to the result.
The answer is 38. Break down the digits like this: 1 0 0 1 1 0 Going right to left, each position represents a higher power of 2, starting with 2^0, which is one, so right the powers of two under the digits, ascending as you move to the left: 1 0 0 1 1 0 32 16 8 4 2 1 Then, just multiply each binary digit by the value below, and you get: 32 + 4 + 2 = 38.
No. For x < 0, it decreases, for x > 0, it increases. In each of these two parts, it is monotic, though.No. For x < 0, it decreases, for x > 0, it increases. In each of these two parts, it is monotic, though.No. For x < 0, it decreases, for x > 0, it increases. In each of these two parts, it is monotic, though.No. For x < 0, it decreases, for x > 0, it increases. In each of these two parts, it is monotic, though.
To find the sum of binary numbers 1101 and 1110, we perform binary addition. Starting from the rightmost bit, we add each pair of bits along with the carry from the previous addition. 1+0 gives 1, 0+1 gives 1, 1+1 gives 0 with a carry of 1, and 1+1 (including the carry) gives 1 with a carry of 1. Therefore, the sum of 1101 and 1110 in binary is 11011.
+1/0 or -1/0 or 0/0