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What direction is the y axis pointing?
up/down
How does one get the formula for an equilateral triangle?
the formula for the area of equilateral triangle with side length a is (a^2)(sqrt(3)/4 ) So draw an equilateral triangle with sides a,a,a. Now divide it into two triangles by bisecting the top angle and extending that line down so it makes a 90 angle with the base. (any angle will do since it is symmetric, but I am trying to help you draw it) Now the new half triangle you have is a 30 60 90 triangle since the top angle is half the original which was 60 and the lower left angle is still 60. The 90 degree angle is the third angle and we are drawing it this way so we have a that the side between the 30 and 90 degree angles is the height of the triangle and we can use 1/bh which is the area formula. The new base has length a and the height is sqrt3(a) because it is a 30-60-90 triangle so 1/2 bxh= 1/2(1/2 )a (sqrt3)a=(1/4)a^2( sqrt3 )since 1/2 base = a/4 and height is sqrt3 x a
Starting with an equilateral triangle with the sides of 2 prove that sin60degrees equals root 3 over 2?
You need a sketch to prove this. and i don't think i can provide one. but il try..u have 3 sides, all of them with a length of 2. this means you have a triangle with all 3 corners equal to one another i.e. 60 degrees. /\ / \ / \ /___\ if this is the initial triangle, draw a line down the middle of the triangle like so: /\ / |\ / | \ /___ \ (difficult to illustrate) now you have one half of the original triangle. this new triangle has 3 corners equaling 60 degrees (at the bottom left), 30 degrees (at the top) and 90 degrees (at the bottom right). using Pythagoras figure out the side lengths. then you will figure out that sin(60) = sq(3)/2
Is this a girl or a boy symbol?
The female gender symbol is a down pointing cross with a circle above ♀
What is the altitude of a equilateral triangle if one side is 6 cm?
An equilateral triangle has all 3 sides the same length. To find the height of a triangle, draw a line from the tip top of the triangle to the middle of the base. You should see 2 triangles now inside your original triangle. We can use Pythagoras' theorem to figure out the length of this line, the height. This theorem will only work with right triangles, which (luckily) we have just created by drawing the height line inside the triangle. The P. theorem says that side squared + side squared = hypotenuse squared. Our hypotenuse is the left or right side of the original triangle, 6 cm. The line we drew down the center is one side, and HALF of the base is the other side for the P. theorem, since the height line of the triangle cuts the base exactly in half, and creates 2 right angles at the base. This line also creates 2 right triangles inside. This is why we can use the P. theorem to help us! But we'll only be using 1 of the inside triangles. (Even though, both are identical) side squared + side squared = hyp. squared (3 cm) squared + ??? squared = 6 squared 9 + ??? squared = 36 ??? squared = 36 - 9 ??? squared = 27 ??? = sqrt(27) We can simplify sqrt(27), or you can use a calculator to approximate it. sqrt(27) = sqrt(9*3) = 3 * sqrt(3)
