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You need a sketch to prove this. and i don't think i can provide one.

but il try..u have 3 sides, all of them with a length of 2. this means you have a triangle with all 3 corners equal to one another i.e. 60 degrees.

/\

/ \

/ \

/___\

if this is the initial triangle, draw a line down the middle of the triangle like so:

/\

/ |\

/ | \

/___ \

(difficult to illustrate)

now you have one half of the original triangle.

this new triangle has 3 corners equaling 60 degrees (at the bottom left), 30 degrees (at the top) and 90 degrees (at the bottom right).

using Pythagoras figure out the side lengths.

then you will figure out that sin(60) = sq(3)/2

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Q: Starting with an equilateral triangle with the sides of 2 prove that sin60degrees equals root 3 over 2?
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