(f+g)(x) = 4x + 8 + 5x -6 => (f+g)(x) = 9x + 2
find f'(x) and f '(c)f(x) = (x^3-3x)(2x^2+3x+5
Answer is D.73
It is 1.2164
if f(x) = 3x - 10, then whatever is put (substituted) for x in the "f(x)" bit is substituted for x in the "3x - 10" bit. Thus f(2a) = 3(2a) - 10 = 6a - 10.
The idea is to replace every "x" by "3", and then do the calculations.
Let, f (x) = - 5x - 9 Therefore, f(x) + 7 = - 5x - 9 + 7 f(x) + 7 = - 5x - 2
f(x)=5x, g(x)=3x-7 gf(x)= = g(f(x)) = g(5x) = 3*(5x) - 7 = 15x-7 So gf(4) = 15*4-7=53
No, f(x) is not the inverse of f(x).
Rearrange for y, let f(x) = y, and find the derivative of f(x) with respect to x: 5x + 3y = -2 y = -(5x+2)/3 = f(x) df/dx = -5/3
f(x)=5x+2
f(x) = x2 + 5x + 1 The roots of this equation are x = -0.2087 and x = -4.7913 (approx).
Follow this example. f(x) = (x+3)/5 To find its inverse, write y=f(x) y= (x+3)/5 Interchange x and y x = (y+3)/5 solve for y in terms of x 5x=y+3 y=5x-3 The inverse of f(x) is f^-1(x) = 5x-3
To find (f-g)(x), we need to subtract g(x) from f(x). So, (f-g)(x) = f(x) - g(x). Substituting the given functions, we get (f-g)(x) = (x+8) - (-4x-3). Simplifying this expression, we get (f-g)(x) = x + 8 + 4x + 3 = 5x + 11. Therefore, (f-g)(x) = 5x + 11.
If I understand this right... f(x) = x2 + 5x + 2 f(x) is a function, in this case a function of x. Using this function, you can say... f(g) = g2 + 5g + 2 f(pi) = pi2 + 5pi + 2 All we're doing is substituting whatever's in the brackets on the other side. Thus... f(2) = 22 + 5*2 + 2
You've given the answer yourself. d=6 and f=3.
(f+g)(x) = 4x + 8 + 5x -6 => (f+g)(x) = 9x + 2