find f'(x) and f '(c)f(x) = (x^3-3x)(2x^2+3x+5
7(3y-2)-(-4y+9)
A minus and a minus makes a plus A plus and a plus makes a plus A minus and a plus or plus and a minus makes a minus 7 - -2 is a minus and a minus Therefore the answer is 7 + 2 = 9
This is the common form of the Pythagorean Theorem. It describes the relationship between the two legs of a right triangle and the hypotenuse.
x^2 + 3x + 2/(-3x) - x^2 - 2=3x-2+2/(-3x)=3x-2-2/(3x)
x - 2
2
7(3y-2)-(-4y+9)
x = -28 / -11^2
x^2 +9 =x^2 -9 9=-9 No solution
-2, 1.74 and 0.46
It is: 9-4 = 5
No
The solutions are: x = 4, y = 2 and x = -4, y = -2
3
104
4 squared minus 2 squared equals 12
Two plus 3 minus 2 times 1 squared plus 4 times 16 squared minus 4 times 2 is equal to 1,019.