x2 + 12x + 32 = (x + 8)(x + 4)
It is: (x+1)(x+4) none of which are prime numbers
It is x^2 -4 = (x-2)(x+2) when factored and it is the difference of two squares
X2 - 16(X - 4)(X + 4)============X2 + 16===========not factorable in real numbers
False
x2 + 12x + 32 = (x + 8)(x + 4)
(x-4)(x-4)
(x-1)(x-4)
(x + 4)(x - 3)
x2 - 2x - 24 = (x - 6)(x + 4)
(x-4) (x+7)
(x+4)(x-2)
(x - 4)(x - 4)
y = x2 - 4x + 4 can be factored into y = (x-2)(x-2) The repeated factor is 2.
I assume x2 + 5x - 36 is the polynomial in the question. First, look for two factors of 36 that have a difference of 5, which would be 9 and 4. It would factor into (x + 9)(x - 4). To double check, multiplying them together results in x2 - 4x + 9x - 36 = x2 + 5x - 36. If the polynomial is 5x2 +7x +2
x2 + 12x + 32 = (x + 4)(x + 8)
(x - 4)(x - 11)