9 - x2 will factor into (3 - x)(3 + x)
x^2+6x-16 (x+2)+(6x-16) x+8+x-16 (x+8)(x-2) here you go :)
x2(x3 + 1) is the best you can do there.
x2-9x = x(x-9)
If you mean "factors", the two monomials have the common factor x2. Divide each factor by x2 to get the other factor.
x2 - 4
x2 - 6x - 16 = (x + 2)(x - 8)
x + 4
(x + 4)(x - 4)
16 + 6x - x2 = 16 + 8x - 2x - x2 = 8*(2 + x) - x*(2 + x) = (8 - x)*(2 + x)
(x + y)(x - y) = 16
It is: (x-4)(x+4)
L2 math.
(x - 16)(x + 3)
x2 - 16 = (x + 4)(x - 4) x2 - 16 is the difference of two squares: a2 - b2 factorises as (a + b)(a -b), thus: x2 - 16 = x2 - 42 = (x + 4)(x - 4)
(x - 8)(x - 2)
(x-4)(x-4)