They are: 97+99 = 196
144 + 196 = 340 so integers are 12 & 14.
x^2 + (x+1 )^2 =365 x^2 +x^2 + 2x +1 =365 2x^2 + 2x = 364 x^2 + x = 182 = (x- 13)(x + 14) x =13, so integers are 13 and 14, squares 169 and 196, which total 365.
The numbers are 195, 196, 197 and 198.
169 < 179 < 196 So, sqrt(169) < sqrt(179) < sqrt(196) and so, 13 < sqrt(179) < 14
97 and 99
They are: 97+99 = 196
The integers are 12 and 14 (144+196=340)
The numbers are 97, and 99.
10+(X)+(X+1)=196 10+2X+1=196 11+2X=196 2X=185 X=92.5 Therefore, ten plus the sum of two consecutive integers can not be even.
144 + 196 = 340 so integers are 12 & 14.
x^2 + (x+1 )^2 =365 x^2 +x^2 + 2x +1 =365 2x^2 + 2x = 364 x^2 + x = 182 = (x- 13)(x + 14) x =13, so integers are 13 and 14, squares 169 and 196, which total 365.
Integers are rational.
All integers are rational numbers.
13 & 14 (169 & 196)
Any one of infinitely many integers of the form 196*k where k is an integer.
The numbers are 195, 196, 197 and 198.