The numbers are 97, and 99.
Let the number be x.15 * x= x+196Then, 15x - x =196‹=› 14 x= 196‹=› x = 14.
132 = 169 < 184 < 196 = 142 So 13 < √184 < 14 So estimating from consecutive whole numbers would give the answer "13 and a bit". But you can do better than that by interpolating. The square-root function is, obviously, not linear but you will not go too far wrong between consecutive integers (unless you are dealing with very small number). 184 is (184-169)/(196-169) = 15/27 of the distance between 132 and 142 so the square root is approx 15/27 = 5/9 of the way from 13 to 14 ie 13+5/9 = 13.555... recurring. In fact, the correct value is approx 13.5647 so the estimate is accurate to 2 decimal places.
Let the number be 'm' & 'm + 2' Hence their squares are m^2 & (m+2)^2 There sum is m^2 + (m+2)^2 = 340 Multiply out he brackets m^2 + m^2 + 4m + 4 = 340 . 2m^2 + 4m + 4 = 340 Divide both sides by '2' m^2 + 2m + 2 = 170 m^2 + 2m - 168 = 0 Factor (m - 12)(m + 14) = 0 Hence m = 12 & m+ 2 = 14 The two consecutive even numbers. 12^2 = 144 14^2 = 196 144 + 196 = 340 As required.
3.14 times 196 is equal to 615.44. This calculation is done by multiplying the decimal number 3.14 by the whole number 196. To find the product, you multiply the whole number by the whole number part of the decimal (196 x 3) and then multiply the whole number by the decimal part (196 x 0.14) before adding the two products together.
97 + 99 = 196
They are: 97+99 = 196
The integers are 12 and 14 (144+196=340)
The numbers are 97, and 99.
10+(X)+(X+1)=196 10+2X+1=196 11+2X=196 2X=185 X=92.5 Therefore, ten plus the sum of two consecutive integers can not be even.
144 + 196 = 340 so integers are 12 & 14.
x^2 + (x+1 )^2 =365 x^2 +x^2 + 2x +1 =365 2x^2 + 2x = 364 x^2 + x = 182 = (x- 13)(x + 14) x =13, so integers are 13 and 14, squares 169 and 196, which total 365.
Integers are rational.
All integers are rational numbers.
13 & 14 (169 & 196)
Any one of infinitely many integers of the form 196*k where k is an integer.
The numbers are 195, 196, 197 and 198.