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What two consecutive integers sum is 196?
The numbers are 97, and 99.
Find the number which when multiplied by 15 is increased by 196?
Let the number be x.15 * x= x+196Then, 15x - x =196‹=› 14 x= 196‹=› x = 14.
What is the Estimate the square root of 184 by finding the consecutive whole numbers it lies between?
132 = 169 < 184 < 196 = 142 So 13 < √184 < 14 So estimating from consecutive whole numbers would give the answer "13 and a bit". But you can do better than that by interpolating. The square-root function is, obviously, not linear but you will not go too far wrong between consecutive integers (unless you are dealing with very small number). 184 is (184-169)/(196-169) = 15/27 of the distance between 132 and 142 so the square root is approx 15/27 = 5/9 of the way from 13 to 14 ie 13+5/9 = 13.555... recurring. In fact, the correct value is approx 13.5647 so the estimate is accurate to 2 decimal places.
What is 3.14 times 196?
3.14 times 196 is equal to 615.44. This calculation is done by multiplying the decimal number 3.14 by the whole number 196. To find the product, you multiply the whole number by the whole number part of the decimal (196 x 3) and then multiply the whole number by the decimal part (196 x 0.14) before adding the two products together.
Find two consecutive positive even numbers the sum of whose squares is 340?
Let the number be 'm' & 'm + 2' Hence their squares are m^2 & (m+2)^2 There sum is m^2 + (m+2)^2 = 340 Multiply out he brackets m^2 + m^2 + 4m + 4 = 340 . 2m^2 + 4m + 4 = 340 Divide both sides by '2' m^2 + 2m + 2 = 170 m^2 + 2m - 168 = 0 Factor (m - 12)(m + 14) = 0 Hence m = 12 & m+ 2 = 14 The two consecutive even numbers. 12^2 = 144 14^2 = 196 144 + 196 = 340 As required.
