First start out by writing an equation in point-slope form because you have a slope and points. So, it will be:
y+3=-2(x-1) use distributive property
y+3=-2x+2 subtract 3 on both sides to get y alone
y=-2x-1 answer
The answer is y=-2x-1
Assuming the point is (9, -4), the equation is y = -4.
The equation is: y = 4x-22
"14" is not a point; you need two coordinates to specify a point.
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
The parallel equation will have the same slope but with a different y intercept
y = 2x + 1.
sda
Assuming the point is (9, -4), the equation is y = -4.
The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0
The equation is: y = 4x-22
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
414
The equation works out as: y = 5x+7
If you mean a slope of 6 passing through the point of (1, 3) then the equation works out as: y = 6x-3
The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0
"14" is not a point; you need two coordinates to specify a point.
If you mean slope of -3 and a point of (2, 4) then the equation is y = -3x+10