y = 2x + 1.
The answe iss..... 6
y=2x+1
Slope: -3 Point: (4, -5) Equation: y = -3x+7
If you mean a point of: (2,1) then the equation works out as y = 3x-5
Given point: (6, 7) Equation: 3x+y = 8 Parallel equation: 3x+y = 25
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
The answe iss..... 6
y=2x+1
y = 2x - 1
It is: y = 2x-6
The equation is (y - 1) = 2(x - 1) or, y = 2x - 1
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
Choose the equation of the line that contains the points (1, -1) and (2, -2).
As a straight line equation: y = -3x+18 in slope intercept form
It is: y-7 = 2(x-3) => y = 2x+1