2x2 -3x - 4 = 0 use the qudratic equation and your answers are 1.137458609 and -2.637458609
x2+7x=-2x2+6 3x2+7x-6=0 (3x-2)(x+3)=0 3x-2=0 or x+3=0 x=2/3 or x=-3
That's not an equation - it doesn't have an equal sign. Assuming you mean 2x2 - 3x - 90 = 0, you can find the solution, or usually the two solutions, of such equations with the quadratic formula. In this case, replace a = 2, b = -3, c = -90.
If you mean 2x^2 -3x +8 = 0 then the discriminant works out as -55 which is less than 0 meaning that the equation has no real roots and so therefore no solutions are possible.
y = 2x2 - 3x + 1 y = (x - 1)(2x - 1) x - 1 = 0 2x - 1 = 0 x = 1 x = 1/2 the answer is 2
The discriminant is 1.
2X2 + 3X - 4 = 0the discriminant is,b2 - 4ac32 - 4(2)(- 4)9 + 32 = 4141 > 1this means there are two real roots to this equation
The discriminant is 25.
The discriminant is -199.
The discriminant is 609.
The discriminant is -11.
There are no real solutions. The discriminant (b squared -4ac) is less than 0, so there are 2 imaginary solutions and 0 real ones.
-7
If: 2x2-3x+1 = 0 Then: x = 1 or x = 1/2
Solve by factoring.2x2 - 3x + 1 = 0
(-2,-1)
2x2 -3x - 4 = 0 use the qudratic equation and your answers are 1.137458609 and -2.637458609