4x2 + 3x - 6 is a second degree polynomial. Since the polynomial function f(x) = 4x2 + 3x - 6 has 2 zeros, it has 2 linear factors. Since we cannot factor the given polynomial, let's find the two roots of the equation 4x2 + 3x - 6 = 0, which are the zeros of the function. 4x2 + 3x - 6 = 0 x2 + (3/4)x = 6/4 x2 + (3/4)x + (3/8)2 = 6/4 + 9/64 (x + 3/8)2 = 105/64 x + 3/8 = ± √(105/64) x = (-3 ± √105)/8 x = -(3 - √105)/8 or x = -(3 + √105)/8 Thus, the linear factorization of f(x) = 4[x + (3 - √105)/8][x + (3 + √105)/8].
64 because 8*8=64. you just have to find the square number.
63 and 64
64 x 65 = 4160
32*24=768 16(8*6)=16(48)=768 64(4*3)=64(12)=768
64=2x2x2x2x2x2
Two to the power of 6 or 2x2x2x2x2x2
The prime factorization of 64 is 2x2x2x2x2x2 or 26.
The prime factorization of 64 with exponents is: 26
The prime factorization of 64 is 2x2x2x2x2x2, or 26 in exponential form.64 = 26
The prime factorization of 64 is 2x2x2x2x2x2 or 26. The prime factorization of 8 is 2x2x2 or 23.
The prime factorization of 64 is 2x2x2x2x2x2 or 26. 2 is the only prime number in the factorization of 64.
No, 8 isn't a prime number. The prime factorization of 64 is 26
== The answer is 64== 2x2x2x2x2x2. ==
26 = 64
That's the prime factorization of 64.
No, 64 isn't prime.