4x2 + 3x - 6 is a second degree polynomial. Since the polynomial function f(x) = 4x2 + 3x - 6 has 2 zeros, it has 2 linear factors.
Since we cannot factor the given polynomial, let's find the two roots of the equation 4x2 + 3x - 6 = 0, which are the zeros of the function.
4x2 + 3x - 6 = 0
x2 + (3/4)x = 6/4
x2 + (3/4)x + (3/8)2 = 6/4 + 9/64
(x + 3/8)2 = 105/64
x + 3/8 = ± √(105/64)
x = (-3 ± √105)/8
x = -(3 - √105)/8 or x = -(3 + √105)/8
Thus, the linear factorization of f(x) = 4[x + (3 - √105)/8][x + (3 + √105)/8].
4x2 - 2x - 12= 2x2 - x - 6= 2x2 - 4x + 3x - 6= 2x(x - 2) + 3(x - 2)= (x - 2)(2x + 3)
If the missing signs are all pluses, that's 4x2 + 3x + 3
The answer to your question, as asked, is that it is a linear equation with one variable, x. 3x + 3 = 9 Subtract 3 from both sides: 3x = 6 Divide both sides by 3: x = 2
3X = 5Y solve for Y Y = 3/5X this is by definition a linear equation solved. You can plat this straight line on a graph.
3x+6
4x2+3x+6+5x+3x+6 = 4x2+11x+12 when simplified
3
(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4(multiply x2 - 3 by x, and subtract the product from the dividend)1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)1. 4x(x - 3) = 4x2 - 12 = 4x2 - 122. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)
3(4x2 - x + 2)
y=4x2+3x+8
4x2 - 3x - 9
4x2 - 6x - 12 = 2 (2x2 - 3x - 6) There are no integer roots, the approximate roots are 2.64 and -1.14
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3x-3x+4x^2+8x=4x^2+8x
4x2 - 2x - 12= 2x2 - x - 6= 2x2 - 4x + 3x - 6= 2x(x - 2) + 3(x - 2)= (x - 2)(2x + 3)
The first equality is: x2 - 5 = -4x2 which gives 5x2 - 5 = 0 which is equivalent to x2 - 5 = 0 The second equality is: -4x2 = 3x which gives 4x2 + 3x = 0 The two results are inconsistent.
x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0