4x2 + 3x - 6 is a second degree polynomial. Since the polynomial function f(x) = 4x2 + 3x - 6 has 2 zeros, it has 2 linear factors.
Since we cannot factor the given polynomial, let's find the two roots of the equation 4x2 + 3x - 6 = 0, which are the zeros of the function.
4x2 + 3x - 6 = 0
x2 + (3/4)x = 6/4
x2 + (3/4)x + (3/8)2 = 6/4 + 9/64
(x + 3/8)2 = 105/64
x + 3/8 = ± √(105/64)
x = (-3 ± √105)/8
x = -(3 - √105)/8 or x = -(3 + √105)/8
Thus, the linear factorization of f(x) = 4[x + (3 - √105)/8][x + (3 + √105)/8].
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4x2 - 2x - 12= 2x2 - x - 6= 2x2 - 4x + 3x - 6= 2x(x - 2) + 3(x - 2)= (x - 2)(2x + 3)
If the missing signs are all pluses, that's 4x2 + 3x + 3
3x+6
The answer to your question, as asked, is that it is a linear equation with one variable, x. 3x + 3 = 9 Subtract 3 from both sides: 3x = 6 Divide both sides by 3: x = 2
From first equation, -y = 3x + 3. Substitute in second equation: -3x + 5(3x + 3) = -21 ie 12x = -36 so x = -3 and y = -(-9 + 3) = 6. Easier method: subtract first equation from second giving -4y = -24 so y = 6, this in first equation gives -6 = 3x + 3, ie 3x = -9 so x = -3