Slope, m, equals (y2-y1)/(x2-x1). Slope is (0-(-1))/(0-(-1)) or 1/1 or 1.
5x2 - 20 = 0x2 - 4 = 0x2 = 4x = +2 and -2
I dont see any related links or files that I need to follow as indicated by your question. the general form of 5x2 - 20x = 15 is... 5x2 - 20x - 15 = 0 ax2 + bx + c = 0
y = 0That's the equation of the x-axis.Its slope is zero.
Remember the standard form of an equation:Y = (slope) x + (y-intercept)Now take your equationY = (-1) x + (0)Compare yours to the standard one.That's how to find them.Now can you identify the slope and y-intercept of the graph of your equation ?
2/5 is the slope
the slope is 0
5x2 + 15x = 0 5x(x + 3) = 0 therefore, x = 0 or x + 3 = 0 that is, x = 0 or x = -3
Slope, m, equals (y2-y1)/(x2-x1). Slope is (0-(-1))/(0-(-1)) or 1/1 or 1.
Slope = 0
The slope is normally represented by m so it is 0.
-2
The discriminant is 385.
5x2 - x - 4 = 0(5x + 4) (x - 1) = 05x + 4 = 05x = -4 ===> x = -(4/5)x - 1 = 0 ==> x = 1
5x2 + 2x - 3 = 0 5x2 + 5x - 3x - 3 = 0 5x(x + 1) - 3(x + 1) = 0 (5x - 3)(x + 1) = 0 So 5x - 3 = 0 or x + 1 = 0 ie x = 3/5 or x = -1
5x2+7x = 12 5x2+7x-12 = 0 (5x+12)(x-1) = 0 x = -12/5 or x = 1
well 5x2=10 and anything x 0=0 so x=0 because 10x0=0