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If two nonvertical lines are perpendicular, then the product of their slope is -1.An equivalent way of stating this relationship is to say that one line is perpendicular to another line if its slope is the negative reciprocal of the slope of the other. For example, if a line has slope 3, any line having slope - 1/3 is perpendicular to it. Similarly, if a line has slope - 4/5, any line having the slope 5/4 is perpendicular to it.
If the line has a slope of 2, then the perpendicular line has a slope of -1/2. The slope of a perpendicular line is the negative reciprocal. Another example would be if the slope of a line is -1/4, then the slope of the perpendicular is 4.
The slope of two lines are perpendicular only if their slopes multiplied together equal -1 (m1*m2 = -1). So if a line has a slope of -3 then a line perpendicular to this one has a slope of -1/-3 or 1/3.
If: y = 2/5x+10 then the perpendicular slope is -5/2x or -2.5x
Slope of a line perpendicular to x-y=16
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Slope of the given line is 3/7 So slope of perpendicular line is -7/3
Slope of given line = -3 Therefore, slope of perpendicular = 1/3
Slope of given line = 3 So slope of perpendicular = -1/3
3X + 5Y = 155Y = -3X + 15Y = (-3/5)X + 3The slope of this line is -3/5.The slope of a line perpendicular to it is 5/3.
For the line 2x + y = 8 , the slope equals ( -2 ) so the required slope of the line which is perpendicular to it is equal to (+1/2 )
The line x = -4 is vertical, so a line that is perpendicular to it is horizontal, so its slope is 0.
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The slope is -0.2
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