Slope of a line = m slope of perpendicular line = -1/m
The slope of a line perpendicular to one with a slope of m is -1/m.
Equation of given line: 3x + y = 15 or y = -3x + 15 Slope of given line = coefficient of x = -3 Slope of perperndicular = -1/(slope of given line) = -1 / (-3) = 1/3
x-3y = 9 -3y = -x+9 y = 1/3x -3 Perpendicular slope = -3
The slope of the perpendicular is -(1/2) .
Slope of a line perpendicular to x-y=16
Slope of the given line is 3/7 So slope of perpendicular line is -7/3
Slope of given line = -3 Therefore, slope of perpendicular = 1/3
Slope of given line = 3 So slope of perpendicular = -1/3
3X + 5Y = 155Y = -3X + 15Y = (-3/5)X + 3The slope of this line is -3/5.The slope of a line perpendicular to it is 5/3.
For the line 2x + y = 8 , the slope equals ( -2 ) so the required slope of the line which is perpendicular to it is equal to (+1/2 )
The line x = -4 is vertical, so a line that is perpendicular to it is horizontal, so its slope is 0.
The slope is -0.2