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Not so sure about angels, but

The sum of the exterior angles of ANY polygon is 360 degrees. The number of sides or vertices, whether the shape is regular or irregular, are irrelevant.

Q: Find the sum of the measures of the exterior angels of a nonagon?

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40

80 degrees.

Each interior angle of a regular hexagon measures 120 degrees. It has a total of 720 degrees of interior angles and a total of 360 degrees of exterior angles.

The sum of the exterior angles of any polygon is 360 degrees.

you add it all

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According to theorem 5.4 Every Exterior angle of a regular polygon measures 360/N so all you would do I dived 360 by the number of sides a Nonagon have which is 9

The measure is 360/9 = 40 degrees.

It doesn't matter what shape it is, the sum of the exterior angels in any polygon is 180.

The sum of the interior angles of a polygon is 2n-4 Right Angles For a nonagon (2x9)-4 RAs = 14x90°=1260° To find the interior angle of a regular nonagon, divide this by 9 which gives 140° To find the exterior angle, subtract this from 180 and you get 40°. The sum of the exterior angles of a polygon is 360°, so for a regular polygon you can also divide this by the number of sides, which in this case also gives: 360° ÷ 9 = 40°

360 degrees

The exterior angles of any polygon add up to 360 degrees.

Each exterior angle of a regular octagon measures 45 degrees

The sum of a regular polygons exterior angles always = 360

40

If it's a regular polygon: 360/number of sides = each exterior angle

80 degrees.

You add together the lengths of the nine sides of the nonagon.