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An exterior angle at the base of an isosceles triangle measures 110 find the measure of the vertex angle?
40
An exterior angle at the base of an isosceles triangle measures 130 find the measure of the vertex angle?
80 degrees.
Find the sum of the interior measures of a regular hexagon?
Each interior angle of a regular hexagon measures 120 degrees. It has a total of 720 degrees of interior angles and a total of 360 degrees of exterior angles.
What is the formula to find the exterior angles?
The sum of the exterior angles of any polygon is 360 degrees.
How do you you find an exterior angle of a triangle?
you add it all
Find the measure of eaxch exterior angle of a regular nonagon?
According to theorem 5.4 Every Exterior angle of a regular polygon measures 360/N so all you would do I dived 360 by the number of sides a Nonagon have which is 9
Find the measure of each exterior angle of a regular nonagon?
The measure is 360/9 = 40 degrees.
How do you find the sum of the exterior angels in a regular poly gon?
It doesn't matter what shape it is, the sum of the exterior angels in any polygon is 180.
What is the measure of an interior angle and an exterior angle of a nonagon?
The sum of the interior angles of a polygon is 2n-4 Right Angles For a nonagon (2x9)-4 RAs = 14x90°=1260° To find the interior angle of a regular nonagon, divide this by 9 which gives 140° To find the exterior angle, subtract this from 180 and you get 40°. The sum of the exterior angles of a polygon is 360°, so for a regular polygon you can also divide this by the number of sides, which in this case also gives: 360° ÷ 9 = 40°
How to Find the sum of the interior angle measures and the sum of the exterior angle measures of a quadrilateral?
360 degrees
Find n if each exterior angle of a regular n-gon has a measure of 40 degreees?
To find ( n ) for a regular n-gon where each exterior angle measures 40 degrees, use the formula for the exterior angle of a regular polygon, which is ( \frac{360}{n} ). Setting this equal to 40 gives the equation ( \frac{360}{n} = 40 ). Solving for ( n ), we find ( n = \frac{360}{40} = 9 ). Thus, the polygon is a nonagon (9-sided polygon).
Describe how you can find the sum of the measures of the exterior angles of a polygon?
The exterior angles of any polygon add up to 360 degrees.
How many ways can you find the sum of measures of the exterior angles of a polygon?
The sum of a regular polygons exterior angles always = 360
Find the measure of each exterior angle of a regular ctagon?
Each exterior angle of a regular octagon measures 45 degrees
An exterior angle at the base of an isosceles triangle measures 110 find the measure of the vertex angle?
40
What is the formula to find the sum of the measures of the exterior angles one at each vertex of a polygon?
If it's a regular polygon: 360/number of sides = each exterior angle
How can you find the sum of the interior Angle measures and the sum of the exterior angle measures of a polygon?
To find the sum of the interior angle measures of a polygon with ( n ) sides, use the formula ( (n - 2) \times 180^\circ ). For the sum of the exterior angle measures of any polygon, regardless of the number of sides, it is always ( 360^\circ ). Thus, you can easily calculate the interior angles based on the number of sides while remembering that the exterior angles sum to a constant value.
