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How can you find the sum of the interior Angle measures and the sum of the exterior angle measures of a polygon?
To find the sum of the interior angle measures of a polygon with ( n ) sides, use the formula ( (n - 2) \times 180^\circ ). For the sum of the exterior angle measures of any polygon, regardless of the number of sides, it is always ( 360^\circ ). Thus, you can easily calculate the interior angles based on the number of sides while remembering that the exterior angles sum to a constant value.
What is the sum of the measures of the interior angles of a regular polygon is each exterior angle measures 120?
To find the sum of the measures of the interior angles of a regular polygon with each exterior angle measuring 120 degrees, we first determine the number of sides in the polygon. The sum of exterior angles of any polygon is always 360 degrees, so the number of sides ( n ) can be calculated as ( n = \frac{360}{120} = 3 ). Since it is a triangle, the sum of the interior angles is given by the formula ( (n - 2) \times 180 ) degrees, which for a triangle (3 sides) is ( (3 - 2) \times 180 = 180 ) degrees. Thus, the sum of the measures of the interior angles is 180 degrees.
How do you find interior and exterior angles of an irregular polygon?
Measure them with a protractor
What is the formula to find the measurement of exterior angles of a hexagon?
For any n-sided regular polygon the exterior angles are 360/n degrees.
If the exterior angles measure 40 degrees in a polygon how many sides does the polygon have?
if the exterior angle is 40 degrees the interior angle of the polygon is 180- 40 = 140 degrees. The equation for sides N is interior angle = 180 x (N-2)/N; solving you find N = 9 sides
Describe how you can find the sum of the measures of the exterior angles of a polygon?
The exterior angles of any polygon add up to 360 degrees.
What is the formula to find the sum of the measures of the exterior angles one at each vertex of a polygon?
If it's a regular polygon: 360/number of sides = each exterior angle
How do you find the measure of exterior angles on a polygon?
The exterior angles of any polygon add up to 360 degrees
How can you find the sum of the exterior angles in any polygon?
The exterior angles of any polygon add up to 360 degrees
Describe how you can find the sum of the exterior angles of a polygon?
The exterior angles of any polygon always add up to 360 degrees
One exterior angle of a regular polygon measures 40 What is the sum of the polygon's interior angle measures?
The sum of a regular polygon's interior angles is always equal to (n-2) * 180, where n is the number of sides in the polygon. Given that one exterior angle measures 40 degrees, we can find the interior angle by subtracting 40 from 180 degrees (since the exterior and interior angles are supplementary) to get 140 degrees. So, the sum of the interior angles of the regular polygon is 140 * n.
What is the formula to find the exterior angles?
The sum of the exterior angles of any polygon is 360 degrees.
How can you find the sum of the interior Angle measures and the sum of the exterior angle measures of a polygon?
To find the sum of the interior angle measures of a polygon with ( n ) sides, use the formula ( (n - 2) \times 180^\circ ). For the sum of the exterior angle measures of any polygon, regardless of the number of sides, it is always ( 360^\circ ). Thus, you can easily calculate the interior angles based on the number of sides while remembering that the exterior angles sum to a constant value.
Find the sum of the measures of the exterior angles of a convex 21-gon?
The sum of exterior angles, of any polygon - convex or concave, and whatever the number of sides - is 360 degrees or 2*pi radians.
How do you find interior and exterior angles of a polygon?
Use a protractor
What is the sum of the measures of the interior angles of a regular polygon is each exterior angle measures 120?
To find the sum of the measures of the interior angles of a regular polygon with each exterior angle measuring 120 degrees, we first determine the number of sides in the polygon. The sum of exterior angles of any polygon is always 360 degrees, so the number of sides ( n ) can be calculated as ( n = \frac{360}{120} = 3 ). Since it is a triangle, the sum of the interior angles is given by the formula ( (n - 2) \times 180 ) degrees, which for a triangle (3 sides) is ( (3 - 2) \times 180 = 180 ) degrees. Thus, the sum of the measures of the interior angles is 180 degrees.
How do you you find a exterior angle sum?
The exterior angles of any polygon add up to 360.
