For 5y-15=5x
5y=5x+15
y=x+3
The y-intercept is (0,3)
To find the x-intercept, substitute 0 in for y in the above
0=x+3
x=-3
So the x-intercept will occur at x=-3, making it (-3,0)
Mark these two points and draw a straight line along the two points and you will get your equation's graph.
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its a simple parobola symmetric about y axis, having its vertex at (0,-4). we can make its graph by changing its equation in standard form so that we can get its different standard points like vertex, focus, etc.
Yes that is correct
By including its plus or minus signs
If: w-7 = 11 Then: w = 18
y = -0.5x plus or minus any number
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factors are (4x + 1)(3x - 2) so y = 0 when x = minus a quarter and x = two-thirds
The equation is y=x(x+1)(x-2)2
-2x=2y-4 2x-y=-5 Answer=(-1,3)
The required equation is: -7x = 63
x = 4 and y = 7
y = -16x2 + 342At the x-intercepts, y=0-16x2 + 342 = 016x2 = 342x2 = 342/16 = 21.375x = plus and minus sqrt(21.375) = approx. plus and minus 4.6233 (rounded)
Without an equality sign and not knowing the plus or minus values of y and 13 the information given can't be considered to be a straight line equation
x = 4 and y = 7 which will satisfy both equations
An equation where x equals 3.
-1/2