x = 4 and y = 7 which will satisfy both equations
x = 4 and y = 7
Choose any value for "x", replace that in the equation, and calculate the corresponding value for "y".
1. simple keep change change, changing it from -2--3 to -2+3=1 or to switch that order to make it even easier on yourself you can make it 3-2=1 but be careful with your signs when switching the order of numbers in the equation. the answer is 1.
It is: (6-3)*(7+4) = 33
This equation is unsolvable since there are two unknowns and only one equation. You would require a second equation in order to solve it.
x = 4 and y = 7
You would need to know what a is equal to in order to calculate this equation.
Choose any value for "x", replace that in the equation, and calculate the corresponding value for "y".
1. simple keep change change, changing it from -2--3 to -2+3=1 or to switch that order to make it even easier on yourself you can make it 3-2=1 but be careful with your signs when switching the order of numbers in the equation. the answer is 1.
It is: (6-3)*(7+4) = 33
This equation is unsolvable since there are two unknowns and only one equation. You would require a second equation in order to solve it.
13 + 7 - (6 + 4) * 2 = 0
Adding a negative number to a negative number makes a larger negative. In order to solve this you add the numbers together as a positive then add a negative sign.
Multiply by 4
In order to answer that, we need an "equation" that shows us the relationship among 'Y', 'A', and 'B'.
It works out that: x = 3 and y = 2
Commutative, not communtative The mathematical property of being able to change the order of the numbers and not change the answer. A plus B equals B plus A (1 plus 3 equals 4, 3 plus 1 equals 4) A times B equals B times A (2 times 5 equals 10, 5 times 2 equals 10) Addition and multiplication are commutative operators A minus B is not necessarily equal to B minus A (6 minus 4 equals 2, 4 minus 6 equals minus 2) A divided B is not necessarily equal to B divided A (9 divided by 3 equals 3, 3 divided by 9 equals one-third) Subtraction and division are not commutative operators