x = 3.5
Quantity x+4 times quantity x+1.
They are at x = -3 and x = -2.
This expression factors as x -1 quantity squared.
(((x*3)/4)+8)-5 = y --------------------------------------------------------------------------------------------------- Assume the number is Y three times the number + 8 = 3Y + 8 1/4 th this quantity is (3Y + 8)/4 then 5 less this quantity = 5 - (3Y + 8)/4 Assume Y = 4 for example then the result is zero Assume Y = 8 for example then the result is -3 Assume Y = zero then the result is +3
-x-3 or -3-x
10x + 10x = 20x
2x + 2 > x + 5
n>3 2x + 2 > x + 5
5(4 + x)
Your answer will depend on the parameters of the instructions. If you're looking for the first derivative, simply use the product rule by changing the denominator to a negative exponent and bringing it up (take the negative square root of the quantity x-2 to the top). Then, follow the rules of calculus and algebra. Wow, that's a mess. Let's see... you get "the quantity x cubed plus 6x squared plus 3x plus 1 times the quantity -1(x-2) raised to the negative second plus the quantity x-2 raised to the negative first times the quantity 3x squared plus 12x plus 3." This is because of the Product Rule. Simplifying (by factoring out (x-2) raised to the negative second and combining like terms) gives us "(x-2) raised to the negative second times the quantity 2x cubed minus 24x minus 7." This can also be written as "2x cubed minus 24x minus 7 all over the quantity x-2 squared." f'(x)= 2x^3-24x-7 (x-2)^2
Cannot determine without solution
x = 3.5
5*(3+x)=15+5x Fifteen plus five times that number
3
x2+5y+4 (i have no idea but)x2+5x+4 = (x+4)(x+1)
irdk