x2-5x+4 = (x-1)(x-4) when factord
When factored it is: (x-9)(x+4)
. x + 4
It is: (x+1)(x+4) none of which are prime numbers
sorry i am not sure but i dont think it has an answer If this equation is: x^2 - 36 = 5x, then: x^2 - 36 = 5x subtract 5x to both sides; x^2 - 5x - 36 = 0 Factor; (x + 4)(x - 9) = 0 x + 4 = 0 or x - 9 = 0 x = -4 or x = 9
x2-5x+4 = (x-1)(x-4) when factored
x2-5x+4 = (x-1)(x-4) when factord
When factored it is: (x-9)(x+4)
(x + 4)(x + 1)
(x - 4)(x - 1)
x3 + 2x2 + 5x + 4 = (x + 1)(x2 + x + 4)
x2-5x-36 = (x-9(x+4) when factored
(x-1)(x-4)
. x + 4
x3 - 4x2 + 5x - 20 = x2*(x - 4) + 5*(x - 4) = (x2 + 5)*(x - 4)
(x-4)(x-1)
I assume x2 + 5x - 36 is the polynomial in the question. First, look for two factors of 36 that have a difference of 5, which would be 9 and 4. It would factor into (x + 9)(x - 4). To double check, multiplying them together results in x2 - 4x + 9x - 36 = x2 + 5x - 36. If the polynomial is 5x2 +7x +2