Quantity x+4 times quantity x+1.
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x2-5x+4 = (x-1)(x-4) when factord
When factored it is: (x-9)(x+4)
. x + 4
It is: (x+1)(x+4) none of which are prime numbers
sorry i am not sure but i dont think it has an answer If this equation is: x^2 - 36 = 5x, then: x^2 - 36 = 5x subtract 5x to both sides; x^2 - 5x - 36 = 0 Factor; (x + 4)(x - 9) = 0 x + 4 = 0 or x - 9 = 0 x = -4 or x = 9