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1. start the program (Connector Symbol- Ovel Shape)
2. Get the input (a number) from the user (n) - (Input/Output Symbol-parallelogram)
3. store the number in an int variable (m=n)
4. Initialize the sum as Zero (sum=0)-(Rectangle)
5. check the decision as while(n>0)-(Diamond Shape)conditional (or decision), represented as a diamond (rhombus)
6.If this yields true then process as follows:(Processing Symbols-Rectangles)
(remainder) r=n%10;
sum=sum+(r*r*r);
n=n/10;
7.check the decision statement again and continue with the process until the condition becomes false.
8.Finally check m with sum
9. If the sum==m Then print the number is an Armstrong-(Output Symbol-parallelogram)
10.Else not an Armstrong
11.Terminate the Program.(Ovel shape)
What else can I help you with?
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