i need a pic of cuson
A flowchart to find the factorial of a given number typically includes the following steps: Start, read the input number, check if the number is less than 0 (return an error for negative numbers), initialize a result variable to 1, and then use a loop to multiply the result by each integer from 1 to the input number. The algorithm can be summarized as follows: if ( n ) is the input number, initialize ( \text{factorial} = 1 ); for ( i ) from 1 to ( n ), update ( \text{factorial} = \text{factorial} \times i ); finally, output the factorial.
Factorials are the product of 1 and all the integers up to the given number. Simply put, 5 factorial or 5! = 5*4*3*2*1
Kat
To determine if a given number is a factorial, you can check if there exists a non-negative integer ( n ) such that ( n! ) equals that number. Start with ( n = 0 ) and compute factorials incrementally (0! = 1, 1! = 1, 2! = 2, etc.) until the computed factorial exceeds the given number. If you find a match during this process, then the number is a factorial; otherwise, it is not. Additionally, you can utilize the property that factorials grow very rapidly, which can help limit the number of calculations needed.
The link has a picture of the flow chart. Too hard to put it in a readable format on Answers.comhttp://en.wikipedia.org/wiki/File:FlowchartExample.png
A flowchart to find the factorial of a given number typically includes the following steps: Start, read the input number, check if the number is less than 0 (return an error for negative numbers), initialize a result variable to 1, and then use a loop to multiply the result by each integer from 1 to the input number. The algorithm can be summarized as follows: if ( n ) is the input number, initialize ( \text{factorial} = 1 ); for ( i ) from 1 to ( n ), update ( \text{factorial} = \text{factorial} \times i ); finally, output the factorial.
Here's a simple Java program to find the factorial of a given number using a recursive method: import java.util.Scanner; public class Factorial { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print("Enter a number: "); int number = scanner.nextInt(); System.out.println("Factorial of " + number + " is " + factorial(number)); } static int factorial(int n) { return (n == 0) ? 1 : n * factorial(n - 1); } } This program prompts the user for a number and calculates its factorial recursively.
Factorials are the product of 1 and all the integers up to the given number. Simply put, 5 factorial or 5! = 5*4*3*2*1
Kat
To determine if a given number is a factorial, you can check if there exists a non-negative integer ( n ) such that ( n! ) equals that number. Start with ( n = 0 ) and compute factorials incrementally (0! = 1, 1! = 1, 2! = 2, etc.) until the computed factorial exceeds the given number. If you find a match during this process, then the number is a factorial; otherwise, it is not. Additionally, you can utilize the property that factorials grow very rapidly, which can help limit the number of calculations needed.
The link has a picture of the flow chart. Too hard to put it in a readable format on Answers.comhttp://en.wikipedia.org/wiki/File:FlowchartExample.png
Pseudo code+factorial
no
flow chart to find whther the given number is perfect or not
#define fact(n) ( n == 0 ? 1 ; (n*(fact(n-1) ) ) )
/*program to find the factorial of a given number*/ #include<stdio.h> #include<conio.h> int fact(int); void main() { int n,c; printf("\n enter the number for which you want to find the factorial"); scanf("%d",&n); c=fact(n); printf("\n the factorial of the number %d is %d",n,fact); getch(); } int fact(int n) { int k; if(n==0) return(1); else k=n*fact(n-1); return(k); }
<html> <script language="vbscript"> n=cint(inputbox("Enter a number")) dim f f=1 if n<0 then Msgbox "Invalid number" elseif n=0 or n=1 then MsgBox "The factorial of given number "&n&" is :"&f else for i=n to 2 step -1 f=f*i next MsgBox "The factorial of given number "&n&" is :"&f end if </script> </html>