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Given sin theta equals 7 over 13 and tan theta is less than 0 find tan theta?
Wiki User
∙ 9y ago
sin(t) = 7/13
cos2(t) = 1 - sin2(t) = (169 - 49)/169 = 120/169
so cos(t) = ±sqrt(120)/13.
But sin(t) > 0, tan(t) < 0 implies t is in the second quadrant
so cos(t) = -sqrt(120)/13
And then tan(t) = sin(t)/cos(t) = -7/sqrt(120) = -0.6390 (approx).
Wiki User
∙ 9y ago
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