-8x+3y=12
3y = 8x+12
y = (8/3)x + 4
So it will be a line with slope 8/3 and y intercept of 4
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4x+3y = 12 3y = -4x+12 y = -4/3x+4
The equation for 3y + 3y = -1 is 3y + 3y = -1.
12-3y = 15 -3y = 15-12 -3y = 3 y = -1
Add 3y to each side: 12y = 24 Divide each side by 12: y = 2.
6x - 3y = 12y intercept at x = 0 is y = 4x intercept at y = 0 is x = 2the graph is straight line passing through the two points: (0, 4) and (2, 0)