You can do the equation Y 2x plus 3 on a graph. On this graph the Y would equal 5 and X would equal to 0.
y=b+x+x^2 This is a quadratic equation. The graph is a parabola. The quadratic equation formula or factoring can be used to solve this.
So, if we have the equation: F(x) = x^2 + 3 this is a function in terms of x, another way to look at this same problem is to write it as: y= x^2 +3. This function may be graphed if that is what you are looking for, the graph will be of a parabola and then the graph will be shifted from the origin up 3 from the origin.
x + y = 5y = -x + 5The graph is a straight line, with [ slope = -1 ], passing through the point [ y = 5 ] on the y-axis.
Let's say you have the quadratic equation x2 - 7x + 12 = 0. Plot the graph of y = x2 - 7x + 12. Where y = 0 (when the graph crosses the x-axis) is a solution to the equation. In this case, it crosses at the points (3,0) & (4,0) so the solutions are x = 3 and x = 4. Now if the graph never touches the x-axis, that means the solutions to the equation are complex numbers.
Move 3 over the right side of the equation so the equation would be x = -3. The graph of this would be a verticle line at x= -3
You can do the equation Y 2x plus 3 on a graph. On this graph the Y would equal 5 and X would equal to 0.
x plus 37467 is referred to as a linear equation since it can be plotted in the x-y graph.
The question contains an expression, not an equation. An expression does not have a graph. Furthermore, even if it were an equation, its form suggests that it would be a linear equation and a linear equation does not open in any direction.
y = x + 3The graph of that equation is a straight line with a slope of 1 (45° rising to the right)and passing through the point y=3 on the y-axis.
yx-3 is not an equation, and it has no graph.
x^3=2x+5 x^3-2x-5=0 Graph the equation or use a calculator. x= 2.09455148
The given equation y=3+x is a linear line with the slope of 1 and y-intercept of 3.
y=x^3
y=b+x+x^2 This is a quadratic equation. The graph is a parabola. The quadratic equation formula or factoring can be used to solve this.
answer is 1
Since no points were given, for any point (x,y), plug the x and y values of the point into the equation. If you get a contradiction, ie 5=3 or something similar, then the point does not lie on the graph.