You can do the equation Y 2x plus 3 on a graph. On this graph the Y would equal 5 and X would equal to 0.
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The x-interceptin is where the graph crosses the y-axis, which is where y equals 0: 0 = 2x + 3 2x = -3 x = -3/2 So the x intercept is as x = -3/2 (and y = 0).
One way would be to graph the two equations: the parabola y = x² + 4x + 3, and the straight line y = 2x + 6. The two points where the straight line intersects the parabola are the solutions. The 2 solution points are (1,8) and (-3,0)
2x(y - 3) + 7(y - 3) = (2x + 7)(y - 3)
2x + 3y = 8 Usually you would solve for y to get the equation in Slope Intercept Form. (y = mx + b) Where (m) is the slope and (b) is the y intercept of the graph. First get the y by itself by subtracting 2x and getting it to the side with the 8. You now have this... 3y = -2x + 8 Now Isolate the variable (y) by dividing by 3. You now have this... y = - 2/3 + 8/3 Now since you have this in Slope Intercept Form, you know - 2/3 is the slope of the line and 8/3, or 2 2/3, is the y intercept on your graph.
Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.