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You can do the equation Y 2x plus 3 on a graph. On this graph the Y would equal 5 and X would equal to 0.

Q: Y 2x plus 3 graph

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The x-interceptin is where the graph crosses the y-axis, which is where y equals 0: 0 = 2x + 3 2x = -3 x = -3/2 So the x intercept is as x = -3/2 (and y = 0).

One way would be to graph the two equations: the parabola y = xÂ² + 4x + 3, and the straight line y = 2x + 6. The two points where the straight line intersects the parabola are the solutions. The 2 solution points are (1,8) and (-3,0)

2x(y - 3) + 7(y - 3) = (2x + 7)(y - 3)

2x + 3y = 8 Usually you would solve for y to get the equation in Slope Intercept Form. (y = mx + b) Where (m) is the slope and (b) is the y intercept of the graph. First get the y by itself by subtracting 2x and getting it to the side with the 8. You now have this... 3y = -2x + 8 Now Isolate the variable (y) by dividing by 3. You now have this... y = - 2/3 + 8/3 Now since you have this in Slope Intercept Form, you know - 2/3 is the slope of the line and 8/3, or 2 2/3, is the y intercept on your graph.

Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.

Related questions

2x plus y = -3 (subtract 2x from both sides) y = -2x - 3 slope = -2 y-intercept = -3

y plus 3 1 2x plus 1 can be graphed by first finding the values of Y and X coordinates.

a straight line with a slope of -2 and a y-intercept of 3

2,4

The x-interceptin is where the graph crosses the y-axis, which is where y equals 0: 0 = 2x + 3 2x = -3 x = -3/2 So the x intercept is as x = -3/2 (and y = 0).

2x + 6y = 6Subtract 2x from each side:6y = -2x + 6Divide each side by 6:y = -1/3 x + 1The graph is a straight line, with a slope of [ -1/3 ], and intersecting the y-axis at the point [ y = 1 ].

y = 2x + 3 is LINEAR. It is a straight line graph with a steepness/gradient of '2' ( The 'x' coefficient). The line passes through the y-axis at '3'

9y + 2x + 3 = 13 + 2xSubtract 2x from each side:9y + 3 = 13Subtract 3 from each side:9y = 10Divide each side by 9:y = 10/9The graph is a straight horizontal line. The slope is zero. The y-intercept is [ y = 10/9 ).

There are no common points for the following two equations: y = 2x + 3 y = 2x - 1 If you graph the two lines, since they have the same slope, they are parallel - they will never cross.

Y = 2X + 3 The graph of this equation is a straight line, with a slope of 2, passing through the point Y=3 on the Y-axis.

A graph that has 1 parabolla that has a minimum and 1 positive line.

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