Yes, it is possible only when the x-intercept
is infinite.
so slope=y/x = 0.
The slope intercept form is y=mx+b where m is the slope and b is the y intercept y=2x-8.
If you mean: y = -4x then the slope is -4 and there is no y intercept because the line cuts through the origin at (0, 0)
y = slope*x + intercept, so y = -8x + 5
y = mx + b where m = slope and b = y-intercept y = 2x + 0 y = 2x
Normally yes, but if the slope passes through the origin (0, 0) then it will have no y intercept.
2y = 8 y = 4 this is the equation of a horizontal line. The slope is 0, and the y-intercept is 4.
Slope=0 Y-intercept=0
To determine the slope and y-intercept of the equation (6 + y = 8), first rearrange it into slope-intercept form (y = mx + b). This simplifies to (y = 2), which indicates that the slope ((m)) is 0 (indicating a horizontal line), and the y-intercept ((b)) is 2. Therefore, the slope is 0 and the y-intercept is 2.
Slope and y-intercept of y equals 2.5x is: Slope is 2.5 and y-intercept is 0
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The slope intercept form is y=mx+b where m is the slope and b is the y intercept y=2x-8.
If you mean: y = -4x then the slope is -4 and there is no y intercept because the line cuts through the origin at (0, 0)
If you mean: y = 3.5x+8 then the slope is 3.5 and the y intercept is 8
It is in slope intercept form. The slope is 0 and the y-intercept is -2.
The y-intercept is 0 and the slope is 1.
4
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