y = mx + b
where m = slope and b = y-intercept
y = 2x + 0
y = 2x
If the slope is 2 and the coordinate is (0, 3) then the equation is y = 2x+3
If you mean a slope of 4 and points of (0, 2) then the equation is y = 4x+2.
We know that the line passes through points (2, 2) and (0, 10) (since the y-intercept is 10).Using these two points, we can find the slope of the line,m = (10 - 2)/(0 - 2) = 8/-2 = 4/-1 = -4.Now by using the slope, m = -4, and the y-intercept, 10, we can write the equation of the line in the slope-intercept form, y = mx + b which isy = -4x + 10.
y = 0That's the equation of the x-axis.Its slope is zero.
The equation of: y = 5x-3 would satisfy the given conditions.
If the equation of a line is in the form ax + by + c = 0 then the slope of the line will be -a/b.
y = 0. You can get this from the slope-intercept equation of the line.
If the slope is 2 and the coordinate is (0, 3) then the equation is y = 2x+3
If the slope is 2 and the coordinate is (0, 3) then the equation is y = 2x+3
If you mean a slope of 4 and points of (0, 2) then the equation is y = 4x+2.
If you mean a slope of 4 and points of (0, 2) then the equation is y = 4x+2.
the slope is 0
We know that the line passes through points (2, 2) and (0, 10) (since the y-intercept is 10).Using these two points, we can find the slope of the line,m = (10 - 2)/(0 - 2) = 8/-2 = 4/-1 = -4.Now by using the slope, m = -4, and the y-intercept, 10, we can write the equation of the line in the slope-intercept form, y = mx + b which isy = -4x + 10.
0. The equation of a horizontal line is y=0*x+b
y = 0That's the equation of the x-axis.Its slope is zero.
The slope equation is y = mx + b where m is slope for y = 3 we have y = 0 (x) +3 so m = 0 = slope So slope is zero line is constant y = 3
Th estandard slope intercept form is y = mx + b where m = slope of line and b = y intercept when x = 0 For a horizontal line m = slope = 0 equation for horizontal line is y = b