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What two numbers have sum of 15 and a product of 56?
8 , and 7. x+y=15 >> x=-y+15 x*y=56 >> y*(-y+15)=56 , then solve for y , put y back into either equation for x.
X plus y equals 10 y equals X plus 8?
x + y = 10 y = x + 8 so, x + (x + 8) = 10 2x + 8 = 10 2x + 8 - 8 = 10 - 8 2x = 2 x = 1 and y = 9 because y = x + 8 y = 1 + 8 y = 9
What is the solution of y x 4 y 3x 8?
If you mean: y = x+4 and y = 3x+8 then x = -2 and y = 2
If the difference of two numbers is 8 and their product is 17. what is the sum of their squares?
Suppose the numbers are x and y.Then (x - y)^2 = x^2 - 2xy + y^2 = x^2 + y^2 - 2xyThat is 8^2 = x^2 + y^2 - 2*1764 = x^2 + y^2 - 34So x^2 + y^2 = 64 + 34 = 98.
What half the product of x and y?
(x+y)/2
The sum of x and y decreased by their product?
The sum of x and y decreased by their product is (x + y)- xy.
What shows the product of 6 and x decreased by the sum 6 and y?
6x - (6 + y)
What is 8 times a number x decreased by y?
It is difficult to tell what expression you are trying to convey. 8 multiplied by x, and then take y away, is 8x-y x take away y, and then 8 multiplied by this number, is 8(x-y) 8 multiplied by x, and divided by y is 8x/y
How do you write four times the product of x and y decreased by 2xy?
4xy - 2xy
What is the answer of 'y decreased by 8'?
y-8
The product of a number and 8 in an equation?
y x 8
What two numbers have sum of 15 and a product of 56?
8 , and 7. x+y=15 >> x=-y+15 x*y=56 >> y*(-y+15)=56 , then solve for y , put y back into either equation for x.
How do you factor this x raised to the power of 8 y raised to the power of 8?
x^8 - y^8 = (x - y)(x + y)(x^2 + y^2)(x^4 + y^4)
What is 3x-2y equals 8?
It is an open sentence. 3x = 3 x X 2y = 2 x Y, If 8 is the product then: x = 4 and y = 2. 3 x 4 = 12 2 x 2 = 4 12- 4 = 8
X plus y equals 10 y equals X plus 8?
x + y = 10 y = x + 8 so, x + (x + 8) = 10 2x + 8 = 10 2x + 8 - 8 = 10 - 8 2x = 2 x = 1 and y = 9 because y = x + 8 y = 1 + 8 y = 9
What is the solution of y x 4 y 3x 8?
If you mean: y = x+4 and y = 3x+8 then x = -2 and y = 2
The sum of two integers is -8 and their product is plus 7 what are the two integers?
short answer -1 and -7 long worked answer let x = one of the integers let y = the other integer x+y = -8 xy = 7 solve for y y = -8 - x plug y in x(-8 - x) = 7 rearrange -x^2 - 8x - 7 = 0 divide both sides by -1 x^2 + 8x + 7 = 0 factor (x + 7)(x + 1) = 0 x = -1, -7 y = -8 - x so y = -8 + 1 = -7 or -8 + 7 = -1 so when x = -1, y = -7 when x = -7, y = -1
