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Find the sum of the reciprocals of two real numbers given that these numbers have a sum of 150 and a product of 40?
1/x + 1/y = (y+x)/xy But y + x = sum = 150, and xy = product = 40 So sum of reciprocals = 150/40 = 3.75
If the sum of two numbers is 7 and there product is 25 what is the sum of there reciprocals?
Suppose the two numbers are x and y. Then, the sum of THEIR reciprocals is 1/x + 1/y = y/xy + x/xy = (y + x)/xy = 7/25
The sum of two number is 10 and their product is 30 the sum of their reciprocals is?
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
If the sum of two numbers is 12 and the product is 24 What is the sum of the reciprocals?
1/x+1/y y/xy+x/xy x+y/xy=12/24 12/24=1/2 1/2 is the answer.
The sum of two numbers is 10 and their product is 20 find the sum of the reciprocal of the number.?
1/x + 1/y y/xy + x/xy (y+x)/xy= 10/20 10/20=1/2 1/2 is the answer.
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