To solve for area:
A=lw (Area equals length times width)
The length and width are both 12. Substitute 12 for l and w.
A=12x12
Multiply.
A=144
The room has an area of 144 units.
To solve for perimeter:
P=2l+2w (Perimeter equals two time the length plus two times the width).
Substitute 12 for l and w.
P=(2x12)+(2x12)
Simplify.
P=24+24
P=48
The room has a perimeter of 48 units.
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12 feet by 12 feet.
Perimeter = 12+12+12+12 = 48
The perimeter of a rectangle is calculated by adding the lengths of all four sides. In this case, the room is 12 feet long and 10 feet wide. To find the perimeter, you add the length of all sides: 12 + 12 + 10 + 10 = 44 feet. Therefore, the perimeter of the room is 44 feet.
12ft x 15ft = 180ft2
180 sq ft if 12 X 15 is actually 12 ft X 15 ft. Otherwise anything you like.