To solve for area: A=lw (Area equals length times width) The length and width are both 12. Substitute 12 for l and w. A=12x12 Multiply. A=144 The room has an area of 144 units. To solve for perimeter: P=2l+2w (Perimeter equals two time the length plus two times the width). Substitute 12 for l and w. P=(2x12)+(2x12) Simplify. P=24+24 P=48 The room has a perimeter of 48 units.
I would assume it to be 42 ft depending if you are talking about the inside of the room or the outside perimeter
A 20 x 20 room will have a perimeter of 20 + 20 + 20 + 20 = 80.
To calculate the number of 12x12 tiles needed for a 10x10 room, you first need to find the area of the room. A 10x10 room has an area of 100 square feet. Since each 12x12 tile covers 1 square foot, you would need 100 tiles to cover the entire room.
Based on the given information, there is no way to determine the perimeter. Assuming the room is a square, then you could take the square root of 246 (≈15.6843871) and multiply that by 4 (≈ 62.7375484), which would be the perimeter of a square room with this area.
144
144 tiles
122
154
A 3x12 room is 36 square feet. This means that to fill the floor in the 3x12 room, it will take 36 tiles that are each 1 square foot (12x12) in size.
the perimeter is how long around it is, like my room is 15 ft around, so therefore my rooms perimeter is 15ft
it will cover a 12x12 room
144 sq ft
2o
It is 144 square feet.
To solve for area: A=lw (Area equals length times width) The length and width are both 12. Substitute 12 for l and w. A=12x12 Multiply. A=144 The room has an area of 144 units. To solve for perimeter: P=2l+2w (Perimeter equals two time the length plus two times the width). Substitute 12 for l and w. P=(2x12)+(2x12) Simplify. P=24+24 P=48 The room has a perimeter of 48 units.
It depends on the shape of your room. If your room is a rectangle then your perimeter is 102 feet.