Q: How can you find the differential equation of a family of circles passing through the origin and having centers on the x axis?

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What is the equation of the vertical line passing through (-5,-2)

Slope: -35 passing through (-5, -1) Equation: y = -35x-176

If the slope is m, then the equation is y - 7 = m*(x + 3)

If the slope is undefined, it is a vertical line. Therefore the equation is x=2.

The equation is y = 5x - 15 or y = 5*(x - 3)

Related questions

What is the equation of the vertical line passing through (-5,-2)

Slope: -35 passing through (-5, -1) Equation: y = -35x-176

The equation is x = 2

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Differential reproduction

If the slope is m, then the equation is y - 7 = m*(x + 3)