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How do I determine the domain and the equation of the vertical asymptote with the equation f of x equals In parentheses x plus 2 end of parentheses minus 1?
Wiki User
∙ 8y ago
The domain of the function f(x) = (x + 2)^-1 is whatever you choose it to be, except that the point x = -2 must be excluded.
If the domain comes up to, or straddles the point x = -2 then that is the equation of the vertical asymptote. However, if you choose to define the domain as x > 0 (in R), then there is no vertical asymptote.
Wiki User
∙ 8y ago
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Determine the equation of any vertical asymptote and the value of x for any hole in the graph of the rational function fx x-2 over xsquared-x-2?
Asymptote's occur when your equation has a denominator of zero Holes may occur when your equation has both a numerator and denominator of zero So... The equation for the denominator equals zero is: x2-x-2 = 0 The equation for both the numerator and denominator equals zero is x - 2 = x2-x-2 = 0 For interests sake... lets solve it. ---- x2-x-2 = 0 (x+1)(x-2) = 0 x = -1, 2 x - 2 = x2-x-2 = 0 x - 2 = 0 x = 2 A vertical asymptote occurs at x = -1 A vertical asymptote or hole may appear at x = 2
When a vertical asymptote is reflected over the x axis what does it become?
It remains a vertical asymptote. Instead on going towards y = + infinity it will go towards y = - infinity and conversely.
All rational functions have more than one vertical asymptote?
false
If a function has a vertical asymptote at a certain x-value then the function is at that value?
Undefined
Does every undefined value of fx lead to a vertical asymptote?
No. For example, in real numbers, the square root of negative numbers are not defined.
What is the vertical asymptote of 4 divided by x2?
2
Does every rational function have more than one vertical asymp tote?
No.The equation x/(x^2 + 1) does not have a vertical asymptote.
True or False if a rational function Rx has exactly one vertical asymptote then the function 3Rx should have the exact same asymptote?
It will have the same asymptote. One can derive a vertical asymptote from the denominator of a function. There is an asymptote at a value of x where the denominator equals 0. Therefore the 3 would go in the numerator when distributed and would have no effect as to where the vertical asymptote lies. So that would be true.
Determine the equation of any vertical asymptote and the value of x for any hole in the graph of the rational function fx x-2 over xsquared-x-2?
Asymptote's occur when your equation has a denominator of zero Holes may occur when your equation has both a numerator and denominator of zero So... The equation for the denominator equals zero is: x2-x-2 = 0 The equation for both the numerator and denominator equals zero is x - 2 = x2-x-2 = 0 For interests sake... lets solve it. ---- x2-x-2 = 0 (x+1)(x-2) = 0 x = -1, 2 x - 2 = x2-x-2 = 0 x - 2 = 0 x = 2 A vertical asymptote occurs at x = -1 A vertical asymptote or hole may appear at x = 2
What did the derivative near the horizontal asymptote shout to the derivative near the vertical asymptote?
I don't know, what?
Can the graph of a polynomial function have a vertical asymptote?
no
How do you find vertical asymptote?
One way to find a vertical asymptote is to take the inverse of the given function and evaluate its limit as x tends to infinity.
When a vertical asymptote is reflected over the x axis what does it become?
It remains a vertical asymptote. Instead on going towards y = + infinity it will go towards y = - infinity and conversely.
Why doesnt the graph of a rational function cross its vertical asymptote?
It can.
Can the graph of a function have a point on a vertical asymptote?
No. The fact that it is an asymptote implies that the value is never attained. The graph can me made to go as close as you like to the asymptote but it can ever ever take the asymptotic value.
All rational functions have more than one vertical asymptote?
false
How do you find horizontal and vertical asymptotes?
finding vertical asymptotes is easy. lets use the equation y = (2x-2)/((x^2)-2x-3) since its a rational equation, all we have to do to find the vertical asymptotes is find the values at which the denominator would be equal to 0. since this makes it an undefined equation, that is where the asymptotes are. for this equation, -1 and 3 are the answers for the vertical ayspmtotes. the horizontal asymptotes are a lot more tricky. to solve them, simplify the equation if it is in factored form, then divide all terms both in the numerator and denominator with the term with the highest degree. so the horizontal asymptote of this equation is 0.
