8
2x-2/x^2+3x-4
4
y = 1. When the degree of your numerator is the same with the degree of your denominator, then y = the ratio of the leading coefficients of the numerator and denominator is the horizontal asymptote.
(x2 - 4)/4x = 12; x ≠ 0 x2 - 4 = 48x x2 - 48x = 4 x2 - 48x + 242= 4 + 242 (x - 24)2 = 4 + 576 x - 24 = ±√580 x = 24 ± 2√145
8
2x-2/x^2+3x-4
6
-4/x2
4
12
The remainder is 8. (x2 + 4)/(x - 2) = (x + 2) + 8/(x - 2) or x2 + 4 = (x - 2)(x + 2) + 8
y = 1. When the degree of your numerator is the same with the degree of your denominator, then y = the ratio of the leading coefficients of the numerator and denominator is the horizontal asymptote.
(x2 - 4)/4x = 12; x ≠ 0 x2 - 4 = 48x x2 - 48x = 4 x2 - 48x + 242= 4 + 242 (x - 24)2 = 4 + 576 x - 24 = ±√580 x = 24 ± 2√145
the awnser is 18.. i think..
(3x4 + 2x3 - x2 - x - 6)/(x2 + 1)= 3x2 + 2x - 4 + (-3x - 2)/(x2 + 1)= 3x2 + 2x - 4 - (3x + 2)/(x2 + 1)where the quotient is 3x2 + 2x - 4 and the remainder is -(3x + 2).
4