That becomes x^2 - x + 1
(2x + 1)(4x^2 - 2x + 1)
(x - 1)(x^2 + x + 1)
This doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: (-17 plus or minus the square root of -671) divided by 12x = -1.4166 + 2.158638974498103ix = -1.4166 - 2.158638974498103iwhere i is the square root of negative one.
A factor.
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x3 + 1 = (x + 1)(x2 - x + 1) The x + 1's cancel out, leaving x2 - x + 1
(2x + 1)(4x^2 - 2x + 1)
125x3 + 1 ???????? 53 * x3 + 1 ================?????
It cannot be simplified algebraically and needs to be calculated.
One is the only factor of 50 that is a cube.
(x - 1)(x^2 + x + 1)
This doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: (-17 plus or minus the square root of -671) divided by 12x = -1.4166 + 2.158638974498103ix = -1.4166 - 2.158638974498103iwhere i is the square root of negative one.
That doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: (-7 plus or minus the square root of -371) divided by 10x = -0.7 + 1.9261360284258224ix = -0.7 - 1.9261360284258224iwhere i is the square root of negative one.
You can. They can be multiplied together or you can divided either one by the other.
That doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: (-1 plus or minus the square root of -3) divided by 2.x = -0.5 + 0.8660254037844386ix = -0.5 - 0.8660254037844386iwhere i is the square root of negative one.
Factor the numerator. x+1 is one of its factors (otherwise, it wouldn't be possible to simplify it). Then cancel the identical factors in the numerator and the denominator.
That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: (-5 plus or minus the square root of -239) divided by 12.x = -0.416666 repeating + 1.288302069478359ix = -0.416666 repeating - 1.288302069478359iwhere i is the square root of negative one.