That doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: (-1 plus or minus the square root of -3) divided by 2.
x = -0.5 + 0.8660254037844386i
x = -0.5 - 0.8660254037844386i
where i is the square root of negative one.
(x2 - x + 1)(x2 + x + 1)
(x + 1)(2x + 5)
No
(x-5i)(x+5i)
3x2 + 10x + 3 = (x + 3)(3x + 1).
Oh, dude, you're hitting me with some math now? Alright, so you're looking at the quadratic expression x^2 + 5x + 4. To factor this, you want to find two numbers that multiply to 4 (the constant term) and add up to 5 (the coefficient of the x term). Those numbers are 1 and 4, so the factored form is (x + 1)(x + 4). That's it, easy peasy lemon squeezy!
(x + 2)(x + 1)
(x+1)(x+8)
6(x + 1)(x + 1)
(x2 - x + 1)(x2 + x + 1)
(x + 5)(x + 1)
Factor out the GCF and get X(X2-X+1).
x(x + 2)
(x-1)(x+2)
2(x + 3)(x + 1)
3(x + 4)(x + 1)
x(x + 9)(x + 1)