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Point slope form is standard form. To change point slope form into general form, simply multiply both sides by the denominator of the slope, and move everything onto one side. e.g: y = (1/4)x + 2 Multiply both sides by 4: 4y = x + 8 Move everything onto one side: 4y - x - 8 = 0
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Standard form to point-slope form?
y=mx+b Ax+By=C Move Ax to before C and change the positive or negative sign.
How do you find point-slope form?
The point slope form of a line is one that contains the point and the slope. It is (y-y1)=m(x-x1) Where (x1,y1) are the point on the line that you are given. The other (x,y) are any x and y and m is the slope. So if we have a point (1,2) just for example, and a slope m=3, then the point slope equation or form is (y-2)=3(x-1) Note: The point slope form is easy to remember. It comes directly from the definition of slope. The slope is the rise over the run, of (change in y values) divided (change in x values) Now call the slope m, and let a point we know be (x1,y1) and any other point on the line (x,y), then the slope is m=(y-y1)/(x-x1). Now multiply both sides by (x-x1) and you have the point slope form.
Describe a situation in which point-slope form would be more useful than slope-intercept form?
You use point-slope form to find the equation of a line if you only have a point and a slope or if you are just given two point. Usually you will convert point-slope form to slope-intercept form to make it easier to use.
How do you change slope-intercept form to point-slope form?
Slope intercept form is y = mx + b. Point slope form is y - y1 = m(x - x1). Here is an example of changing slope-intercept form to point-slope form: Change y = 3x + 2 to point slope form: y = 3x + 2 Subtract 2 from each side: y -2 = 3x The equation y-2 = 3x is in point-slope form. It can be rewritten as y-2 = 3(x-0), showing that the line passes through the point (0,2), but is doesn't need to be. (The x1 and y1 represent one point on the line, it doesn't matter which one. Therefore, there are many different equations for the same line in point-slope form. For example, the equation y -2 = 3x is the same line as the equation y - 11 = 3(x - 3), which is the same line as the equation y + 4 = 3(x + 2).)
How do you change an equation of point-slope intercept to standard form?
The pint-slope intercept form of the equation of a line is: y = mx + b The general form is: Ax + By = C. So, y = mx + b subtract mx to both sides; y - mx = b -mx + y = b multiply by -1 to both sides; mx - y = -b This is the general form.
How do you write point slope form in standard form?
Point slope form is standard form. To change point slope form into general form, simply multiply both sides by the denominator of the slope, and move everything onto one side.
How do you write in standard from point slope form?
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What is the standard form for a slope intercept?
y=mx+b. Standard form is Ax+By=C. To get to standard form from slope intercept, Move slope times x over to the y side and change the positive or negative sign.
How do you change from standard form to slope intercept?
Solve the standard form for the dependent variable, commonly 'y'.
Can you change point slope intercept form?
Yes.
Standard form to point-slope form?
y=mx+b Ax+By=C Move Ax to before C and change the positive or negative sign.
What is the equation of a line in standard form?
The standard form equation of a line is y=mx+b. M represents the slope; slope is the change in x over the change in y. B represents the y-intercept.
Who do you change from slope intercept form to standard form?
This is stupid! Why do you even need m help?!
What is slope -8 -2-2 in standard form?
In standard form, there is no slope for three numbers.
How do you find point-slope form?
The point slope form of a line is one that contains the point and the slope. It is (y-y1)=m(x-x1) Where (x1,y1) are the point on the line that you are given. The other (x,y) are any x and y and m is the slope. So if we have a point (1,2) just for example, and a slope m=3, then the point slope equation or form is (y-2)=3(x-1) Note: The point slope form is easy to remember. It comes directly from the definition of slope. The slope is the rise over the run, of (change in y values) divided (change in x values) Now call the slope m, and let a point we know be (x1,y1) and any other point on the line (x,y), then the slope is m=(y-y1)/(x-x1). Now multiply both sides by (x-x1) and you have the point slope form.
Describe a situation in which point-slope form would be more useful than slope-intercept form?
You use point-slope form to find the equation of a line if you only have a point and a slope or if you are just given two point. Usually you will convert point-slope form to slope-intercept form to make it easier to use.
What is the standard form of a slope?
In the standard form of a linear equation:y = mx + bm is the slope* * * * *The above is the slope-intercept form, not the standard form, which isax + by + c = 0The standard form can be converted to the slope intercept form by rearranging, as follows:by = -ax - cso y = -(a/b)x -(c/b)And then, the slope (or gradient) is (-a/b).
