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Write an equation for a line with a slope of 2 through (4 -2) in standard form.?
To write the equation of a line in standard form (Ax + By = C) with a slope of 2 that passes through the point (4, -2), we can start with the point-slope form: (y - y_1 = m(x - x_1)). Substituting the point and the slope gives us (y + 2 = 2(x - 4)). Simplifying this, we get (y + 2 = 2x - 8), or rearranging it leads to (2x - y = 10). Thus, the standard form of the equation is (2x - y = 10).
How do you write anequation in point slope form?
Given a point P(a,b) and slope m, the point slope equation is (y - b)/(x - a) = m
How do you write the point-slope form of an equation of the line described?
No line described, but here is the point slope form. Y - Y1 = m(X - X1) =============
What is slope -8 -2-2 in standard form?
In standard form, there is no slope for three numbers.
What is the difference between the point slope formula and the slope intercept form of a straight line?
The point-slope formula of a straight line is expressed as (y - y_1 = m(x - x_1)), where (m) is the slope and ((x_1, y_1)) is a specific point on the line. In contrast, the slope-intercept form is given by (y = mx + b), where (b) represents the y-intercept, the point where the line crosses the y-axis. Essentially, the point-slope form is used to write the equation of a line given a point and its slope, while the slope-intercept form is used to express the line in terms of its slope and y-intercept.
How do you write in standard from point slope form?
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Can you write an equation in standard form for a line satisfying the given conditions through the point 0 and 4 with a slope of 5?
The standard form is: 5x - y + 4 = 0
Write an equation for a line with a slope of 2 through (4 -2) in standard form.?
To write the equation of a line in standard form (Ax + By = C) with a slope of 2 that passes through the point (4, -2), we can start with the point-slope form: (y - y_1 = m(x - x_1)). Substituting the point and the slope gives us (y + 2 = 2(x - 4)). Simplifying this, we get (y + 2 = 2x - 8), or rearranging it leads to (2x - y = 10). Thus, the standard form of the equation is (2x - y = 10).
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point 1 1?
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
How do write an equation of a line when given the slope a point of the line?
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
How do you write anequation in point slope form?
Given a point P(a,b) and slope m, the point slope equation is (y - b)/(x - a) = m
Write in slope intercept form the equation of the line that is parallel to the given line and passes through the given point?
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
How do you write the point-slope form of an equation of the line described?
No line described, but here is the point slope form. Y - Y1 = m(X - X1) =============
How do you change point slope into standard form?
Point slope form is standard form. To change point slope form into general form, simply multiply both sides by the denominator of the slope, and move everything onto one side. e.g: y = (1/4)x + 2 Multiply both sides by 4: 4y = x + 8 Move everything onto one side: 4y - x - 8 = 0
What is slope -8 -2-2 in standard form?
In standard form, there is no slope for three numbers.
What is the difference between the point slope formula and the slope intercept form of a straight line?
The point-slope formula of a straight line is expressed as (y - y_1 = m(x - x_1)), where (m) is the slope and ((x_1, y_1)) is a specific point on the line. In contrast, the slope-intercept form is given by (y = mx + b), where (b) represents the y-intercept, the point where the line crosses the y-axis. Essentially, the point-slope form is used to write the equation of a line given a point and its slope, while the slope-intercept form is used to express the line in terms of its slope and y-intercept.
The point-slope form of a line is y plus y1 m(x plus x1) where m is the slope and (x1 y1) is a point on the line?
The point-slope form of a line is typically written as ( y - y_1 = m(x - x_1) ), where ( m ) represents the slope of the line and ( (x_1, y_1) ) is a specific point on the line. This formula is useful for writing the equation of a line when you know the slope and one point. By rearranging the equation, it can be transformed into slope-intercept form or standard form if needed.
