The binomial usually has an x2 term and an x term, so we complete the square by adding a constant term. If the coefficient of x2 is not 1, we divide the binomial by that coefficient first (we can multiply the trinomial by it later). Then we divide the coefficient of x by 2 and square that. That is the constant that we need to add to get the perfect square trinomial. Then just multiply that trinomial by the original coefficient of x2.
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false, in order to be one 8 would have to be a square number which it is not. So the constant term in the trinomial would need to be 4, 9, 16 etc.
To make the expression y^2 + 8y + c a perfect square trinomial, we need to find the value of c that completes the square. The formula to complete the square is (b/2)^2, where b is the coefficient of the y-term, which is 8 in this case. So, (8/2)^2 = 16. Therefore, the value of c that makes the trinomial a perfect square is 16.
81.
A perfect square is a binomial squared, like (x+3)^2. You would calculate this by remembering: Square the first, twice the product, square the last. So x^2 (square the first), plus 6x (twice the product), plus 9 (square the last), so we get x^2+6x+9. We can factor this in reverse to see that this is a perfect square. With this simple trick, you can solve for perfect squares.